25x^2-(1/16)y^2=0

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Solution for 25x^2-(1/16)y^2=0 equation: 


x in (-oo:+oo)

25*x^2-((1/16)*y^2) = 0

25*x^2+(-1/16)*y^2 = 0

25*x^2 = -(-1/16*y^2) // : 25

x^2 = 1/400*y^2

x^2 = 1/400*y^2 // ^ 1/2

abs(x) = 1/20*y

x = 1/20*y or x = -(1/20*y)

x in { 1/20*y, -(1/20*y) }

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